Question

Sara selects two cards at random from a standard deck of fifty-two cards. Which of the following could be used to calculate the probability that she will select two even numbered cards if she does not replace the first card before selecting the second? Note: For this problem, face cards and aces are not numbered cards.

sixteen over fifty-two times sixteen over fifty-one

sixteen over fifty-two times fifteen over fifty-one

sixteen over fifty-two times fifteen over fifty-two

sixteen over fifty-two times sixteen over fifty-two

Answer 1

there are 52 cards and 16 even numbers, so first choice would be
16/52

Answer 2

now since it has NO replacements then total cards left 51 and even numbers 15

Answer 3

so what do you think would be the answer ?

Answer 4

Number of cards: 52
Number of even cards: 4 suits x 5 numbers (2, 4, 6, 8, 10) = 20
* Face cards are only J, Q, K

Step 1: Selecting the first card w/o replacement:
Probability of even = 20 / 52

Step 2: Selecting the second card w/o replacement
Probability of even = (20-1) / (52-1)
*after step 1, there is one less even card

Total probability = Step 1 x Step 2.