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Someone please help. To approach the runway, a small plane must begin at 9 degrees descent starting from the height of 1,125 ft above the ground. How many ft from the runway is the airplane at the start of this approach?Round the distance to the nearest foot. A. 1139 ft B. 7103 ft C. 7192 ft D. 7191 ft
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angle of depression = angle of elevation, so that angle equals 9
apply sin ratio, and u can find out x
Wait. I have no clue how to set up the equation. Would it look like this?: sin(1125/9)
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Hahahaha wow ok I know that's not right.
sin (angle) = (opposite SIDE) / (hypotenuse SIDE) sin (9) = (1152) / (?)
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