What is the graph of the absolute value inequality?
\[[x-5] \ge y - 2\]
I like your name, I'll do my best to explain ^^
So let's start with some random plots. What are some sets of values that prove this statement?
x-5 and y-2
I mean ordered pairs, like for example, (8, 2) works.
Oh ok
We can eliminate choices this way, so what graphs already don't work?
In other words, which graphs don't include (8, 2) in their shaded region?
B and D
D I agree with, but why B?
Sorry, C and D
Yep, that's correct. So how about you try and test a point that A has, but B doesn't have? That way we can eliminate one or the other next and get our answer.
I think A is my answer
You are right, but would you care to explain your reasoning? I just want to make sure you got it for the right reasons.
-2 works with A
sans -
Wait a second, I just double-checked this on wolfram, and the graphs don't even match.
Is the inequality written correctly?
Yes
That's weird, because there is actually a different way of doing this. What you can do is rearrange the inequality to look like: y<= Ix-5I - 2
Sorry, I mean +2
A shortcut to finding the vertex would be to shift the vertex according to the constants inside and outside the absolute value.
So the constant inside the absolute value is -5, and the constant outside is 2. The inside constant means we shift the vertex from the origin 5 units to the RIGHT (if it were +5, left), and the outside constant means we then shift it up 2 units (-2 would have meant 2 units down).
|dw:1373479544711:dw|
Join our real-time social learning platform and learn together with your friends!