My answer isn't exactly matching the signs of the given answer and I know this may sound like a stupid question but I've confused myself. Does xy+x+y=x^2y^2 become
xy+x+y-x^2y^2=0 OR xy+x+y+x^2y^2=0

Question

My answer isn't exactly matching the signs of the given answer and I know this may sound like a stupid question but I've confused myself. Does xy+x+y=x^2y^2 become
xy+x+y-x^2y^2=0   OR  xy+x+y+x^2y^2=0

amistre64 · Answer

xy+x+y=x^2y^2   is this your initial function?

wesdg1978 · Answer

Yes

amistre64 · Answer

and what are you trying to do with it?

wesdg1978 · Answer

Well I did implicit differentiation and got the answer and my answer is the same as one of the four options, except for the sign.

amistre64 · Answer

xy + x + y  = x^2y^2

xy:  x'y + xy'
x:  x'
y:  y'
x^2y^2:   x^2' y^2 + x^2 y^2'
            :  2xx' y^2 + x^2  2yy'

assuming this is "with respect to x";  x' = dx/dx = 1

y + xy' + 1 + y' = 2x y^2 + x^2  2yy'

collect the y's to factor out

xy' + y' - x^2 2yy' = 2x y^2 - y - 1

y' (x + 1 - 2x^2 y) = 2x y^2 - y - 1

and divide
$$y' = \frac{2x y^2 - y - 1}{x + 1 - 2x^2 y}$$
simplify as wanted

wesdg1978 · Answer

Yeah, that's the answer they give, but this is what I got:|dw:1373480204646:dw|