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Mathematics 15 Online
OpenStudy (anonymous):

another radical question?

OpenStudy (anonymous):

5 radical 11 - 12 radical 11 - 2 radical 11 Help simplify please?

OpenStudy (anonymous):

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jimthompson5910 (jim_thompson5910):

let x = radical 11

jimthompson5910 (jim_thompson5910):

so you have 5x - 12x - 2x

OpenStudy (anonymous):

You can treat rad 11 as any other variable. If you have five of something, subtract twelve of them, and subtract another two, how many will you be left with?

OpenStudy (anonymous):

@jim_thompson5910 so that would be the answer? the potential answers I have include the radical sign... :/

jimthompson5910 (jim_thompson5910):

what does 5x - 12x - 2x simplify to?

OpenStudy (anonymous):

@vinnv226 I am not sure Im confused with what you mean ..

OpenStudy (anonymous):

@jim_thompson5910 -9x?

jimthompson5910 (jim_thompson5910):

remember we let \(\large x = \sqrt{11}\)

jimthompson5910 (jim_thompson5910):

so -9x turns into \(\large -9\sqrt{11}\)

jimthompson5910 (jim_thompson5910):

so this means \[\large 5\sqrt{11}-12\sqrt{11}-2\sqrt{11} = -9\sqrt{11}\]

OpenStudy (anonymous):

oh wow! that was easy haha I get it! so if the number under the square root sign is the same you just add/sub/whatever the other numbers?

jimthompson5910 (jim_thompson5910):

exactly, think of \(\large 5\sqrt{11}\) and \(\large -12\sqrt{11}\) as like terms which can be combined

jimthompson5910 (jim_thompson5910):

once you get in the habit, you won't have to replace the radicals with x, but it helps to do that to see what's going on

OpenStudy (anonymous):

wow thanks so much I actually understand most of the questions on this homework now :)

jimthompson5910 (jim_thompson5910):

that's awesome, glad it's all clicking now

OpenStudy (anonymous):

how about though if the 3 is above the squareroot like this:

OpenStudy (anonymous):

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