What mass of water at 20.0°C must be allowed to come to thermal equilibrium with a 1.5-kg cube of aluminum initially at 163.0°C to lower the temperature of the aluminum to 57.0°C? Assume any water turned to steam subsequently recondenses.

Question

anonymous · Answer

Still need help @biogirl?

anonymous · Answer

For thermal equilibrium:
Qnet = 0
Qwater + QAl = 0

anonymous · Answer

Qwater = -QAl

anonymous · Answer

General equation: Q = m*C*$$DeltaT$$

anonymous · Answer

So...
$$m _{w}*C _{w}*DeltaT _{w} = - m _{Al}*C _{Al}*DeltaT _{Al}$$

anonymous · Answer

Cw=4180 J/kg*K
Tw=(57-20)
mAl=1.5 kg
Cal=904 J/kg*K
TAl=(57-163)

mw = ?

anonymous · Answer

One equation, one unknown, solve for the mass of the water.