Question

s

Answer 1

if you have a parabola
ax^2 + bx +c

the peak occurs at x= -b/(2a)

to find the peak, you put in that value for x and evaluate the expression

Answer 2

in your case, t
do you know what a and b are in your case ?

Answer 3

the screen shot I see has 277 for b

Answer 4

but now it's different... 229

Answer 5

ok, so t= 23.367 (or 23.4 as you already said)

put that into your expression

Answer 6

t = -b/(2a)

b is +229 and a is -4.9
so you will get a positive #

Answer 7

yes, but the formula is -b (minus b)

-b/(2a)

Answer 8

see
http://regentsprep.org/Regents/math/ALGEBRA/AC4/LPara.htm

Answer 9

so isnt it -229/ 2(-4.9)

yes but I would write it so isnt it -229/ (2*-4.9)

Answer 10

yes, that matches what I got

Answer 11

I assume you can do part c, using the quadratic formula, with h(t)=0

Answer 12

what #'s are you using in

\[ \frac{1}{2a} \left( -b \pm \sqrt{b^2 - 4 a c} \right) \]