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PLEASE: Simplify...(9X)^-2
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1/9x^2
the negative makes it a fraction
By the Law of Exponents: \[(ab)^n = (a)^n (b)^n\] Thus, \[(9x)^-2 = (9)^-2 (x)^-2\] 9^-2 = 1/81 x^-2 = 1/x2
Ok, so I write it as a fraction? the answer is:1/9x^2 ??
yupsiieeesss
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or 1/81x^2
1/81x^2...this is a fraction where 1 is placed over the 81 with 81 having an exponent of 2?
I am confused...is the correct answer 1/9x^2 or is the correct answer 1/81x^2
both LOL
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