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solve square(x+5) = square(x^2-15)
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Does "square(...)" mean square root of "..."?
yes sorry @SithsAndGiggles
\[\begin{align*} \sqrt{x+5}&=\sqrt{x^2-15}\\ x+5&=x^2-15\\ x^2-x-20&=0 \end{align*}\]
Left side can be factored
(x-5)(x+4) @SithsAndGiggles
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Yep. \[(x-5)(x+4)=0~\Rightarrow~x=\cdots\]
4? @SithsAndGiggles
since it cant be negative right
For the left equation to be true, you must have either \[x-5=0~~~\text{or}~~~x+4=0\] Or equivalently, \(x=5\) or \(x=-4\). The 4 can be negative because when you plug it into the original equation, you have \[\sqrt{-4+5}=\sqrt{(-4)^2-15}\\ \sqrt{1}=\sqrt{16-15}\\ 1=1\]
thank you! @SithsAndGiggles
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