Question

For x^2-y^2=5, dy/dx=x/y
How do I then find d^2y/dx^2?

Answer 1

that is the second derivitive..

Answer 2

For the second derivative, I get (y-x)/y^2 , but that's not an answer choice.

Answer 3

what are the choices

Answer 4

Nor is the answer you posted.

Answer 5

what are the choices

Answer 6

A) dy/dx =x/y; d2y/dx2 =(y - x2)/y2

B) dy/dx =x/y; d2y/dx2 =(y2 - x2)/y3

C) dy/dx =x/y; d2y/dx2 =(y2 - x2)/y2

D) dy/dx = -x/y; d2y/dx2 =(y2 - x2)/y3

Answer 7

oh use quoitent rule

Answer 8

That gets (y-x)/y^2