Question

PLZ HELP MEDALS!!!! Consider the infinite geometric series.

Answer 1

a/1-r

Answer 2

series : -4, -4(1/3) , -4(1/3)^2 .......

so the first term is represented by a = -4
common ratio(r) = 1/3

and since we need to sum this series , the sum (S) = a/(1-r)

Answer 3

? i take it thats the sum

Answer 4

so it would converge right? ty !

Answer 5

yes because the common ratio is < 1

Answer 6

got it thank ya!

Answer 7

welcome!!