A saturated solution of ammonium sulfate, (NH4)2SO4, in water at 30 °C contains 78.0 g (NH4)2SO4 per 100.0 g H2O. What is the molality of this solution?

Question

chmvijay · Answer

molality =  moles of ammonium sulfate /Kg of solvent 

moles of ammomium sulfate = gram/ molecular weight =78/132.6    =

100 gram of water = 0.1Kg o water
plug both values in the first equation u get it

anonymous · Answer

thanks mate, just figured it out a few min ago. Calculated it and it came out to be 5.9M.

chmvijay · Answer

yaaa 5.88~ 5.9M ur right