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LAST QUESTION ! I PROMISE ! PLEASE HELP ! What is the sum of the geometric sequence 4, 12, 36 . if there are 9 terms?
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find r then use the formula in finding the sum of geometric series... r stands for the ratio of the first and the next term...
a1= 4 r=12/4=3
\[\Sigma = a\frac{1-r^n}{1-r}\]
\[a \left( \frac{ 1-r ^{n} }{ 1-r } \right)\] a is the first term r is the "common ratio" between terms n is the number of terms
geometric sequence.... sorry for using the term 'series'
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No, series is right
hahahnp ! now what am I supposed to do with that equation
substitute the values
You already know \(a\) and \(r\)/ \(n\) is the number of terms, 9.
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