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Mathematics 7 Online
OpenStudy (anonymous):

Use the triangle in the coordinate plane to find the perimeter.

OpenStudy (anonymous):

OpenStudy (ivettef365):

find the distance using the formula

OpenStudy (unklerhaukus):

use the Pythagorus theorme to find each side

OpenStudy (anonymous):

Find the length of AB, BC, CA using distance formula. Add them up to get perimeter.

OpenStudy (phi):

can you the length of AB ?

OpenStudy (anonymous):

it is 13.45

OpenStudy (anonymous):

AB is down 2 over 4?

OpenStudy (anonymous):

\[AB = \sqrt{(5-1)^2 + (3-5)^2}\]

OpenStudy (phi):

yes, so you have a triangle withs legs 2 and 4 use c^2 = 2^2 + 4^2

OpenStudy (anonymous):

20

OpenStudy (phi):

you mean c^2 = 20 what is c ?

OpenStudy (anonymous):

4.5

OpenStudy (phi):

remember to take the square root of both sides

OpenStudy (phi):

now make a note AB= 4.5 can you find AC ?

OpenStudy (anonymous):

up 3 over 2

OpenStudy (anonymous):

so c^2 is 13?

OpenStudy (phi):

yes

OpenStudy (anonymous):

c is 3.6

OpenStudy (phi):

c= sqrt(13) = 3.6 so we now have AB= 4.5 AC= 3.6 what is BC ?

OpenStudy (anonymous):

down 5 over 2

OpenStudy (anonymous):

c^2 is 29

OpenStudy (anonymous):

c is 5.3

OpenStudy (phi):

are you sure ?

OpenStudy (phi):

sqrt 29 is 5.385 if you round it, you get 5.4

OpenStudy (anonymous):

would the 5 be a negative?

OpenStudy (phi):

no, for these problems, distance is always assumed to be positive. the only problem is sqrt(29) is close to 5.4 than 5.3 (be careful about rounding) finally, what is the perimeter ?

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

13.5

OpenStudy (phi):

yes

OpenStudy (anonymous):

ok thanks

OpenStudy (anonymous):

wait how do you round the sqrt?

OpenStudy (phi):

see http://www.khanacademy.org/math/algebra/linear-equations-and-inequalitie/more-analytic-geometry/v/distance-formula for how they want you to do these problems (in case you don't have a graph, and can't count the squares)

OpenStudy (anonymous):

by the first, second, or third number?

OpenStudy (phi):

rounding is a rule: if you round to the nearest tenth, you look at the digit to the right of the tenth digit 1.23 the 2 is in the tenths place. look at the digit to its right, the 3 if the digit is 5 or bigger round up. otherwise, just drop the fractions example: 1.23912 round to the nearest tenth: look for the tenths place: 2. look to the right: a 3 3 is less than 5, so just drop all the digits to the left of 2. you get 1.2 example 1.2513 now you have a 5, so round up to 1.3

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

so 5.830 it would be 5.9?

OpenStudy (phi):

normally, when doing these problems, keep a few more digits than you really need, then round at the very end. 3 or 4 decimals are good to keep. then round to what the answer wants at the end 5.83 to the nearest ones is 6 (find the ones place:5 look to the right, see 8 is 5 or bigger and round up) 5.83 to the nearest tenths: find the tenths: 8, look to its right and see 3. 3 is less than 5 so just drop the digits to the right of 8 to get 5.8

OpenStudy (anonymous):

ok help me with one more triangle please i dont understand it

OpenStudy (phi):

ok, new post!

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