Use the triangle in the coordinate plane to find the perimeter.
find the distance using the formula
use the Pythagorus theorme to find each side
Find the length of AB, BC, CA using distance formula. Add them up to get perimeter.
can you the length of AB ?
it is 13.45
AB is down 2 over 4?
\[AB = \sqrt{(5-1)^2 + (3-5)^2}\]
yes, so you have a triangle withs legs 2 and 4 use c^2 = 2^2 + 4^2
20
you mean c^2 = 20 what is c ?
4.5
remember to take the square root of both sides
now make a note AB= 4.5 can you find AC ?
up 3 over 2
so c^2 is 13?
yes
c is 3.6
c= sqrt(13) = 3.6 so we now have AB= 4.5 AC= 3.6 what is BC ?
down 5 over 2
c^2 is 29
c is 5.3
are you sure ?
sqrt 29 is 5.385 if you round it, you get 5.4
would the 5 be a negative?
no, for these problems, distance is always assumed to be positive. the only problem is sqrt(29) is close to 5.4 than 5.3 (be careful about rounding) finally, what is the perimeter ?
ok
13.5
yes
ok thanks
wait how do you round the sqrt?
see http://www.khanacademy.org/math/algebra/linear-equations-and-inequalitie/more-analytic-geometry/v/distance-formula for how they want you to do these problems (in case you don't have a graph, and can't count the squares)
by the first, second, or third number?
rounding is a rule: if you round to the nearest tenth, you look at the digit to the right of the tenth digit 1.23 the 2 is in the tenths place. look at the digit to its right, the 3 if the digit is 5 or bigger round up. otherwise, just drop the fractions example: 1.23912 round to the nearest tenth: look for the tenths place: 2. look to the right: a 3 3 is less than 5, so just drop all the digits to the left of 2. you get 1.2 example 1.2513 now you have a 5, so round up to 1.3
ok
so 5.830 it would be 5.9?
normally, when doing these problems, keep a few more digits than you really need, then round at the very end. 3 or 4 decimals are good to keep. then round to what the answer wants at the end 5.83 to the nearest ones is 6 (find the ones place:5 look to the right, see 8 is 5 or bigger and round up) 5.83 to the nearest tenths: find the tenths: 8, look to its right and see 3. 3 is less than 5 so just drop the digits to the right of 8 to get 5.8
ok help me with one more triangle please i dont understand it
ok, new post!
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