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Mathematics 10 Online
OpenStudy (anonymous):

I HATE ALL THESE SURFACE AREAS!!! What is the surface area of the cone? https://nafccsd3647-fchs-ccl.gradpoint.com/Resource/1998126,72F,0,0,0,0,0/Assets/testitemimages/geometry_b/surface_area_and_volume/mc041-1.jpg

OpenStudy (whpalmer4):

Do you have a formula to use?

OpenStudy (anonymous):

I do not, unfortunately..

OpenStudy (whpalmer4):

The surface area of the cone is going to be the area of the base + the area of the side. The area of the base is simply \(A_b = \pi r^2\) or in this case\[A_b = \pi (7 \text{ cm})^2 = 49 \pi\text{ cm}^2\]

OpenStudy (chmvijay):

ind first S that is S^2 =h^2+r^2 = 24 ^2 +7^2 surface area of cone = pie r^2+ pie rs

OpenStudy (chmvijay):

S= 25

OpenStudy (whpalmer4):

The area of the side (lateral surface)is given by \[A_l = \pi r l\]where \(l\) is the slant height. We can find it by the Pythagorean theorem, as it is just the hypotenuse of the right triangle formed by the radius of the base and the height of the cone. \[l^2 = r^2+h^2 \]\[l = \sqrt{r^2+h^2} = \sqrt{(7 \text{ cm})^2 + (24 \text{ cm})^2} = \sqrt{625 \text{ cm}^2} = 25 \text{ cm}\]

OpenStudy (anonymous):

147π cm2 175π cm2 224π cm2 273π cm2 These are the answers they're giving me..?

OpenStudy (whpalmer4):

\[A_l = \pi(7\text{ cm})*(25\text{ cm}) = 175\pi \text{ cm}^2\]\[SA = A_b+A_l = 175\pi \text{ cm}^2 + 49\pi\text { cm}^2 =\]

OpenStudy (chmvijay):

surface area = *49 + 25* 7 = 224 pie

OpenStudy (chmvijay):

224π cm2

OpenStudy (anonymous):

Yeah.. Palmer, your version is a LOT easier to read now that I look at it!

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