HELP PLEASE!! really quick! Find the sum of the first 9 terms of the following sequence: 6, 18, 54. How do i go about solving this?
The formula for the sum of n terms is \[S _{n}=\frac{a(r ^{n}-1)}{r-1}\] where a is the first term and r is the common ratio. In this case the common ratio is 3. Now you just need to plug values into the formula.
Okay, that's what i thought. How do i know what r is? Or rather, how do i figure out r?
I told you the value of r already. It is found by division of successive terms: \[r=\frac{18}{6}=?\]
I was just wondering how to figure it out. Is it always the second number divided by the first?
I got 59,046?
You can find r by dividing any pair of successive terms. So in the sequence that is given \[r=\frac{54}{18}\]
Ahhhh, okay. i get it. I got 59,046... Is that right?
Good work! Your answer is correct.
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