Question

Find y'. y=(x^4-3x^2+5)^3

Answer 1

chain rule:

d/dx f(g(x)) = f'(g(x))*g'(x)

f(x) = x^3
g(x) = x^4 -3x^2 + 5

Answer 2

i can walk you through it if you'd like

Answer 3

would be awesome

Answer 4

okay so i understand what you have already typed...

Answer 5

but what do i do with that?

Answer 6

you'll want to find f'(x) and g'(x).

f'(x) = 3x^2
g'(x) = 4x^3 - 6x

f'(g(x)) = 3(x^4 -3x^2 + 5)^2

y' = 3(x^4 -3x^2 + 5)^2 * (4x^3 - 6x) = f'(g(x))*g'(x)

might seem complicated but it'll come without thinking with practice; i've developed tricks to avoid writing it all out