Question

rewrite the following fraction by rationalizing the denominator. 7/(√3x + √(x-4))

Answer 1

multiply the denominator by itself and also the numerator by the dominator

Answer 2

this is what i had but my teacher said i have to simplify it more
7(√3x-√(x-4) / 2(x+2)

Answer 3

I know tat u have to do that

Answer 4

start by distributing the 7

Answer 5

ok I distributed it to to the numerator

Answer 6

somebody help me

Answer 7

\[\frac{7}{\sqrt{3x}+\sqrt{x-4}}\]or?
\[\frac{7}{\sqrt{3}x+\sqrt{x-4}}\]

Answer 8

1st one

Answer 9

\[\frac{7\sqrt{3}\sqrt{x}-7\sqrt{x-4}}{2x+4}\]
This is your final answer, which you get by multiplying both numerator and denominator by the denominator.

Answer 10

so u would put both the 3 and x under two different radical signs??

Answer 11

You can, it doesn't really matter too much.

Answer 12

so if I write it JUST like you did, it would be correct??

Answer 13

Technically, yes.

Answer 14

k