f(X) = (sqrt(x-3))/((x+8)(x-2)
find domain of function

Question

f(X) = (sqrt(x-3))/((x+8)(x-2)
find domain of function

campbell_st · Answer

well looking at the denominator x cannot be -8 or 2

either value would result in a zero denominator which is undefined.

now looking at the numerator  

x must be greater than or equal to 3 

because if x is less than 3 you are looking at negative square roots.


so the domain of the function is 

$$x \ge3$$

anonymous · Answer

see thats exactly what i thought, but these are my options
 x > 0

 All real numbers

 x ≥ -3, x ≠ 2

 x ≠ -8, x ≠ -3, x ≠ 2

campbell_st · Answer

are you sure the numerator is correct... looking at the answers its appears that the numerator is

$$\sqrt{x + 3}$$

anonymous · Answer

sorry you are right, it is what + 3

campbell_st · Answer

so then what value can't you have in the numerator 

its 

$$x \ge -3$$

combine this with the values in the denominator and you'll get a domain

anonymous · Answer

the closest one to that is the third answer but it doesnt have x isn't equal to -8

campbell_st · Answer

well x can't go as low as -8 so you are looking at 

$$x \ge -3,...x \ne2$$

anonymous · Answer

oh okay now i understand. thnakyou