Question

Can you help me solve this? I'm not quite sure how to do it. I have two equations:
n+q=9
(0.05)n+(0.25)q=1.05

Answer 1

Ok, we can either do substitution which may be more involved. Or we can do elimination. What would you care for?
\[n+q=9\]
\[0.05n+0.25q=1.05\]

Answer 2

either is fine(:

Answer 3

Let's do elimination.
First we we should choose a variable to eliminate first. Let's go with x.
We would multiply the top equation by -0.05
\[-0.05\times(n+q=9)\]=
\[-0.05n-0.05q=-0.45\]
and we still have the second equation
\[0.05n+0.25q=1.05\]

Answer 4

We would add them together top to bottom. Can you do that for me?

Answer 5

Okay. I'm a bit confused on how to add them though.

Answer 6

If I set it up I have this:

but what do I do where there is a n+q?

Answer 7

Then you simply solve for q!

Answer 8

Then we can plug that value into one of the other equations.

Answer 9

Oh, okay.

Answer 10

Did what I just did make sense to you?

Answer 11

yes, but I assume that the 0.20q+0.60 is supposed to be 0.20q=0.60?

Answer 12

Yeah, sorry! Silly typo.

Answer 13

Okay! And then we just fill in q in the other equation and solve?

Answer 14

Correct, what did you get as a value for q?

Answer 15

3

Answer 16

Correct! So when you plug it into the first equation we were given.
\[n+q=9\]
\[n+3=9\]
n=?

Answer 17

6

Answer 18

Correct!
n=6
q=3

Answer 19

Great, thank you so much! I've been having a bit of a hard time understanding how to do these types of problems, and you cleared it up!

Answer 20

No problem! I love algebra, it is fun to me however geeky that may sound lol
If you have any other questions feel free to tag me in a question and I will do my best to help!

Answer 21

Great, thank you so much! (: