The figure below shows Quadrilateral CDBE inscribed in a circle with center A. The paragraph proof with missing statement proves that its opposite angles are supplementary. Which statement can be used to fill in the blank space? Given that CDBE is a quadrilateral inscribed in a circle with center A, ∡DCE and ∡DBE are inscribed angles. Since the measure of an inscribed angle is one-half the measure of its intercepted arc, ∡DCE is half of arc DBE and ________________________________________________. Since arc DBE and arc DCE add up to the whole circle, or 360 degrees, the total of
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@amistre64 can you help me wuth this question afterwards if your fine with that.
∡CBE is half of arc DCE ∡DBE is half of arc DCE ∡DCE is half of arc DBE ∡EDC is half of arc ECD
@phi and @campbell_st can you guys help me???
well, its the other part of the arc setup ....
angle dbe to arc dce
do you know how to do this phi??
probably
you have to take it line by line, and make sense of each line. first ∡DCE and ∡DBE are inscribed angles. can you find those angles in the picture ? do you know what " inscribed angle" means?
formed when two secant lines of a circle intersect a circle
∡DCE is half of arc DBE what does that mean ?
that mean that it ishalf of arc DBE
yes, now notice that arc DBE plus arc DCE is the whole circle, 360º make sense ?
yeah i believe on thinking like that would help.
now what angle is 1/2 of arc DCE ?
so the possible answer can be arc DBE is half of arc DCE??
not arc DBE, *inscribed angle* DBE
i mean angle DBE
yeah.... sorry
so the answer will be inscribed angle DBE is half of arc DCE?? because that is what i am believing the answer will be that because of you hints it makes the most sense.
so we have these facts ∡DCE = 1/2 arc DBE ∡DBE = 1/2 arc DCE add together: ∡DCE + ∡DBE = 1/2 arc DBE + 1/2 arc DCE factor out the 1/2 ∡DCE + ∡DBE = 1/2 ( DBE + DCE) but we know DBE +DCE (arcs) = 360 degrees
and we get ∡DCE + ∡DBE = 1/2 (360) ∡DCE + ∡DBE = 180 degrees that is the proof they are going through. they want you to fill in the the part ∡DBE = 1/2 arc DCE
ok thanks for your help!!!
and if you remember this result, it might come in handy to prove things... if you can remember that a quadrilateral inscribed in a circle has opposite angles that add up to 180
ok
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