Question

check answer please? medal for best

Answer 1

Problem?

Answer 2

Try again

Answer 3

What's:
\[\sqrt{4*6}\]

Answer 4

should be 2 root6, yes?

Answer 5

on this question i kept getting an answer that wasnt listed

Answer 6

Show me your work

Answer 7

k gimme a second ill scan the document

Answer 8

I assume you put the equation into standard form
\[ x^2 +6x + 3=0 \]
with a=1, b= 6, c= 3

Answer 9

sorry i couldn't get it all in one snip

Answer 10

yes, except you divide 2 into both terms up top (not just the 6)

Answer 11

Yea, thanks phi..

Answer 12

@phi what do you mean... where exactly did i go wrong?

Answer 13

when you add fractions 1/5 + 2/5 you can write it as \( \frac{1+2}{5} \)
or vice versa

Answer 14

You have to take out roots first, then simplify it

Answer 15

\[\frac{6}{2}\pm\frac{\sqrt{24}}{2}\]

Answer 16

you should divide 2 into -6 and into the square root part because all of that is over 2

Answer 17

-6* excuse me... silly typo

Answer 18

@austinL can you clarify what you DID mean to write please?
and @phi im still not really getting what youre trying to say

Answer 19

look at the original formula it has a top and a bottom (= 2a)

that 2a divides *INTO EACH TERM UP TOP*

Answer 20

@Luigi0210 so i cant divide (-6/2) before i simplify root24?

Answer 21

oooh, thanks @phi, sorry

Answer 22

yes you can do -6/2

but you also have to do \sqrt(24)/2

Answer 23

\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]
\[\frac{-6}{2}\pm\frac{\sqrt{24}}{2}\]

Answer 24

what would (root24)/2 be?

Answer 25

Well, you would simplify the it first, and divide that by 2.

Answer 26

you did you correctly, sqrt(4*6) = 2 sqrt(6)
now divide by 2

Answer 27

Yea, simplify roots then divide, either the whole thing or by parts

Answer 28

\[\sqrt{24}\] simplified is \[2\times\sqrt{6}\]
So we have
\[\frac{2\times\sqrt{6}}{2}=?\]

Answer 29

is that (root6)/2 ?

Answer 30

No, if we have a 2 on top, and a 2 on bottom, they cancel right?

Answer 31

yeah, but only on that side, right? because it can be rewritten as (2/2)((root6)/2)

Answer 32

am i right, @phi ?

Answer 33

Wait, no. You cant do that.

Answer 34

That is for addition, not multiplication.

Answer 35

@marissalovescats

Answer 36

? @austinL then can you tell me how to fix my original question?

Answer 37

in your post, you are correct down the second to last line

Answer 38

now you can do -6/2 ± sqrt(24)/2

can you simplify that ?

Answer 39

-b+-sqrootb^2-4ac/2a.

x^2+6x+3

a=1
b=6
c=3

Plug into quadratic equation.

Answer 40

@phi:
-3 root12 ?

Answer 41

You started out correct.
\[x^2+6x=-3\]
\[x^2+6x+3=0\]
\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]
\[x=\frac{-6}{2}\pm\frac{\sqrt{24}}{2}\]

Here is where we got off.
You just cancel out the 2's.
\[x=-3\pm\sqrt{6}\]

Answer 42

\[ \frac{\sqrt{24}}{2} = \sqrt{ \frac{24}{4}} = \sqrt{6}\]

Answer 43

or
\[\frac{\sqrt{24}}{2} = \frac{2\sqrt{6}}{2} = \sqrt{6}\]

Answer 44

okay i get it now!

Answer 45

you can use a calculator to check.... by 2 is the same as sqrt(4)
and
sqrt(24)/sqrt(4) is the same as sqrt(24/4)

Answer 46

so my final answer is -3 +/- root6?

Answer 47

if square roots are fuzzy, you can refresh your memory with
http://www.khanacademy.org/math/algebra/exponent-equations/exponent-properties-algebra/v/simplifying-square-roots

but I think you know this

Answer 48

is my final answer going to be -3 +/- root6 ?

Answer 49

scroll up and look at one of my previous posts. I go through it and arrive at the final answer.

Answer 50

yes

Answer 51

oh okay thanks!