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Geometry 12 Online
OpenStudy (anonymous):

What is the surface area of the cylinder?

OpenStudy (anonymous):

OpenStudy (mathstudent55):

The surface of a cylinder is made up of three parts. One part is the lateral surface which is a rectangle with length 2(pi)rh. The other two parts are identical. They are the circular bases. The area of each one is (pi)r^2.

OpenStudy (anonymous):

\(\int_0^{15}12\pi\)dx

OpenStudy (anonymous):

So for this one.. It'd be 252pi^2?

OpenStudy (anonymous):

Radius = 6, so 2(6*6 * pi) = 72pi is the total area of the two circular bases, Pi*Diameter* height=12x 15 x pi = 180pi is the area of the lateral surface, the sum of these two= 180pi+72pi=252pi

OpenStudy (mathstudent55):

\(d = 12 ~ft\), so \(r = 6 ~ft\) \(h = 15 ~ft\) \(SA = 2 \pi rh + 2\pi r^2\) \(= 2 \pi (6 ~ft)(15 ~ft) + 2 \pi (6 ~ft)^2\) \(= 180 \pi + 72 \pi \) \(= 252 \pi ~ft^2\)

OpenStudy (mathstudent55):

@ElaineDunlap You are correct.

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