Question

if m^15 = 48/y and m^13 = 2/6y and m>0 what is the value of m? show work and there are no choices

Answer 1

well look at it this way

\[m^{15} =m^2 \times m^{13}\]

so doing some substitution

\[m^{15} = m^2 \times \frac{2}{6y}\]

which becomes

\[\frac{48}{y} = m^2 \times \frac{2}{6y}\]

divide both sides by 2/6y

and you get

\[\frac{48}{y} \times \frac{6y}{2} = m^2\]

this should allow you to find m

Answer 2

so then i cross multiply to find y then plug y in to find m?

Answer 3

well looking at the 2 fractions on the left, cancel common factors and you

evaluate then find the value of m