Find x. A. 3 B. square root of 3 C. 9 D. square root of 6
\[\cos 30 = \frac{ x }{ 2\sqrt{3} } \]We also know that\[\cos 30 = \frac{ \sqrt{3} }{ 2 }\]So,\[\frac{ x }{ 2\sqrt{3} } = \frac{ \sqrt{3} }{ 2 }\]
Can you finish it from here, @chrissychris ?
how do you divide that or is that the final answer
It's not the final answer, you have to multiply both sides of the equation by: (2)[sqrt(3)] Are you able to do that?
no can you explain that please?
\[\frac{ x }{ 2\sqrt{3} } \times 2\sqrt{3} = \frac{ \sqrt{3} }{ 2 } \times 2\sqrt{3}\]\[x \times \frac{ 2\sqrt{3} }{ 2\sqrt{3} } = \frac{ 2\sqrt{3}\sqrt{3} }{ 2 }\]\[x \times 1 = \frac{ \cancel2\sqrt{3}\sqrt{3} }{ \cancel2 }\] x = 3
All good now, @chrissychris ?
how does \[\sqrt{3} and \sqrt{3} \] =3?
The square root of 3 times the square root of 3 = 3 That follows from the definition of square root.
oh ok thanks
The square root of a number is that quantity that when multiplied by itself gives you back the original number.
ya thank you very much
haha ok
uw! Good luck in all of your studies and thx for the recognition! @chrissychris
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