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Mathematics 19 Online
OpenStudy (anonymous):

Similar Triangles Attachment

OpenStudy (anonymous):

Directrix (directrix):

Corresponding sides of similar triangles are in proportion. The order of the vertices in the similarity statement Tri ABC ~ Tri DEF tells you how to set up the extended proportion.

OpenStudy (anonymous):

so cross multiply

Directrix (directrix):

AB/DE = BC/EF = AC/DF Look at the diagram and fill in the numbers to see which two ratios to use. 5/DE = BC/12 = 8/15 --> @Ambbiiee Check to see if the side lengths are in the right place. If so, we can solve for BC right off the bat.

Directrix (directrix):

Oh, we are looking for DE.

Directrix (directrix):

5/DE = BC/12 = 8/15 so 5/DE = 8/15 Cross multiply and solve for DE. @Ambbiiee

OpenStudy (anonymous):

8DE=75

Directrix (directrix):

DE = 75 divided by 8 and then DE = ?

OpenStudy (anonymous):

9.375=DE

OpenStudy (anonymous):

do i do the same for this one too? just cross multiply right ? @Directrix

Directrix (directrix):

Here, you are finding angles. Corresponding angles are congruent in similar triangles.

Directrix (directrix):

Which angle in Tri QPR corresponds to angle S in Tri TSV?

OpenStudy (anonymous):

umm 6

Directrix (directrix):

I don't see an angle with a measure of 6. You are looking at the SIDES of the triangles. That is not what we are doing. We are looking at the ANGLES of the triangles. Look again and post what you think.

OpenStudy (anonymous):

ohh 86

Directrix (directrix):

Vertex S corresponds to vertex P so yes, it is 86 degrees.

OpenStudy (anonymous):

thanks

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