Question

3x+(1-x)4=2(4-x)

I got 'No answer' but I'm not sure if it's correct =/

Answer 1

3x+4-4x=8-2x
-x+4=8-2x
-4 +2x
-x=8
x=-8

Answer 2

I'm kinda confused about the (1-x)4 thing....

Answer 3

its just a different way of writing a problem of distribution. Just think about the four being on the left side (the opposite side)

Answer 4

Right...but most times on this site...people write it like that when they mean it to be an exponent... just want to make sure...

Answer 5

ah i see

Answer 6

@KawasumiKimiko

Answer 7

yeah because i thought that (1-x)4 was equal to 4(1-x), which it is

Answer 8

unless, as johnweldon pointed out, it could be an exponent, but idk...

Answer 9

which is why I was a little hesitant of writing the answer to the question

Answer 10

@KawasumiKimiko is the equation:

\[3x+(1-x)^4=2(4-x)\]

or

\[3x+(1-x)4=2(4-x)\]

?

Answer 11

@KawasumiKimiko is the 4 at the end of the parentheses an exponent or is it just a term that can be distributed into the parentheses?

Answer 12

@johnweldon1993 the second one.

Answer 13

Ahh okay...the @Jamierox4ev3r has done it *almost correctly* above

3x+(1-x)4=2(4-x)

distribute the 4 into the parenthesis...and the 2 into the other parenthesis

3x+4-4x=8-2x

subtract 4 from both sides

3x+4-4x=8-2x
-4 -4

3x -4x=4 -2x

simplify the left hand side

3x - 4x = -1x or just -x...so

-x = 4 - 2x

Add 2x to both sides

-x = 4 - 2x
+2x +2x

x = 4

Just remember @Jamierox4ev3r ....what you do to 1 side...you do to the other...so when you subtract 4...you subtract it from BOTH sides...and when you add 2x...you add 2x to BOTH sides...

Answer 14

Thank you guys so so so so much! ^^ sorry for all the trouble :3

Answer 15

No problem! :)