Similar Triangles
So you can set up your proportion to solve this \[\frac{ 5.5 }{ 6 } = \frac{ 19.25 }{ 6 + x }\] You can cross multiply and solve for 'x'
\[\frac{ 114 }{ 33x }\]
Not quite...when you cross multiply you multiply 5.5 times (6 + x) and 6 times 19.25 and set thm equal to each other so we get \[5.5(6 + x) = 33 + 5.5x\] and \[6 \times 19.25 = 115.5\] so altogether we have: \[33 + 5.5x = 115.5\] Can you solve for 'x' now?
x=15
Perfect!
can we try another one ?
Sure...
Alright...so this time let me explain the proportion a bit more before I set it up....similar triangle are equal to each other...just changed by some scale factor....but mainly equal to each other...so we compare the height of the smaller to the height of the bigger...and the length of the smaller to the length of the bigger....so that would be: \[\frac{ 2 }{ 5 } = \frac{ h }{ 10 + 5 }\] *10 + 5 for the bigger triangles length because it does include the 5 of the smaller triangle.... So now again...cross multiply and solve for h
\[\frac{ 5h }{ 30 }\]
Remember you dont put it back into a fraction...you set the 2 proportions equal to each other...so it would be \[5h = 30\]
h=6
There ya go!!
thanks (:
No problem! Good work! :)
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