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With the two diagonals being known quantities, you can find the edge length with the Pythagorean theorem. One side of each of those triangles is half of KM, and the other side is half of JL. Do you need more assistance than that?
what is the formula for the Pythagorean theorem @whpalmer4
\[a^2+b^2 = c^2\] if \(a\) and \(b\) are the lengths of the sides and \(c\) is the hypotenuse
Have you figured out the perimeter yet?
no
can you figure out the sides of those triangles?
\[6^{2}+8^{2}=c ^{2}\] @whpalmer4
well, that's close — but 6 and 8 are the full diagonals, not the sides of the triangles.|dw:1373610378395:dw|
\[4^{2}+3^{2}=360\] @whpalmer4
no :-( 3 and 4 are the legs of the triangle. c is the hypotenuse. \[3^2 + 4^2 = c^2\]\[9+16=c^2\]\[c=\]
perimeter is \(4*c\)
i think the answer is 5 @whpalmer4
which answer is 5, the hypotenuse, or the perimeter?
hypotenuse @whpalmer4
okay. so what is the perimeter? that's what the question wants to know
can i add 9+16/2 @whpalmer4
no. you found 1 side of the rhombus. the perimeter is 4 sides. all the sides of a rhombus are identical, right?
I did tell you a few posts ago exactly what to do to find the perimeter :-) good luck, I'm turning in for the night.
okay thanks good night
hint: 5 + 5 + 5 + 5 =
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