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A set of data with a mean of 45 and a standard deviation of 8.3 is normally distributed. Find the value that is –2 standard deviations away from the mean. a.61.6 b.28.4 c.43.0 d.20.1
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the formula to find z is:\[z=\frac{x-mean}{sd}\] solving for x we get:\[mean+z(sd)=x\] they give you the mean, sd, and z values to play with
or if we simply reason it out: -2 standard deviation; when 1 standard deviation is equal to 8.3 is 45 - 8.3 - 8.3
28.4
correct
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