A coin of questionable fairness is tossed 10 times per set of trials for two sets of trials. The outcomes are THTHTHTHHT and TTTHTTHTTH (T = Tails; H = Heads). Which model can you most likely rule out on the basis of this simulation?

Question

anonymous · Answer

A.The probability of heads is 40%. 
B. The probability of heads is 30%.
C. The probability of heads is 35%
.D. The probability of heads is 70%

anonymous · Answer

probability of head is less than 50% in each set (50% in first one and 30% in second one).
So, i guess we can rule out 70%.
Not sure. Confirm it!

anonymous · Answer

so its probably b or c

kropot72 · Answer

Heads came up 8 times in a total of 20 tosses. Therefore the experimental probability of heads is 8/20 = 0.4 or 40%. Which of the four choices is least likely to agree with the experimental probability?

anonymous · Answer

b and c

anonymous · Answer

ad d

kropot72 · Answer

Only one of the choices must be chosen as being the least likely to agree with the experimental probability of 40%. Obviously choice A (The probability of heads is 40%) is the most likely. Which choice is the least likely?

anonymous · Answer

d

kropot72 · Answer

You are correct with your choice :)

anonymous · Answer

i didnt understand the question til i read it again. thanks

anonymous · Answer

So, the coin is more biased towards tail !

kropot72 · Answer

You're welcome :)