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Mathematics 14 Online
OpenStudy (anonymous):

Having an issue with these...Find an explicit rule for the nth term of the sequence. -5, -25, -125, -625, ...

OpenStudy (anonymous):

This one will actually be easier than the last one since we are given the first term. That way, we already know "a" which is -5. We also can re-write the sequence: -5(1, 5, 25, 125, . . . ) And since the general expression for the nth term is (a)[r^(n-1)] we can see we are dealing with powers of "5": (-5)[5^(n-1)]

OpenStudy (anonymous):

All good now, @worne001 ?

OpenStudy (anonymous):

okay, cool. if the numbers were positive, the same formula and steps are used right?

OpenStudy (anonymous):

Yes. Another comment about this problem, though. It looks at first like you can also write: (-1)[5^n] And that would be ok, but it is better to show "r" with a "n-1" power.

OpenStudy (anonymous):

So, you just go with the first term having a factor in it of r^(n-1) which is just "1".

OpenStudy (anonymous):

Okay, thanks @tcarroll010

OpenStudy (anonymous):

You are very welcome! @worne001

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