Question

What is the correct classification of the system of equations below?

14x + 2y = 10
y + 7x = -5

Answer 1

Divide the first equation by 2.
Then write the x and y terms in the same order as in the second equation.

Answer 2

What did you get?

Answer 3

are they parallel?

Answer 4

Did you do what I asked you to?

Answer 5

yes i had that already i was asking what classification they were

Answer 6

A. parallel
B. coincident
C. intersecting
D. x = 10, y = 2

Answer 7

If you did what I asked you to do, then now subtract one equation from the other.
What do you get?

Answer 8

wouldnt they just all cancel out?

Answer 9

I don't know. I haven't solved this problem. I 've asked you to do a few things, and I haven't seen anything you've done, so I can't tell.

Answer 10

y=-7x+5
y=-7x-5
they just cancel out if i subtract right?

Answer 11

Ok. Now I see.
Now subtract the second equation from the first equation.
What is y - y?

Answer 12

they cancel each other out....right? 0

Answer 13

y = -7x + 5
y = -7x - 5
I just reread what you wrote above. You are correct. The lines are parallel. That means there is no solution to this system of equations.

Answer 14

ty

Answer 15

You can see the lines are parallel because they have the same slope and different y-intercepts.

Answer 16

oh alright

Answer 17

Also, if you subtract the equations,

y = -7x + 5
(-) y = -7x - 5
-----------------(subtract)
0 = 0 + 10
0 = 10

you get 0 = 10 which is false. That means the system of equtions is inconsistent, meaning it has no solution.

Answer 18

The reason I told you the above is that there are two ways of concluding this system has no solution.
1. The graphical way is: by noticing the lines a parallel. Since they don't intersect, there is no solution.
2. The algebra way: by noticing that when the equations are subtracted, you get a false statement, that means there is no solution.

Answer 19

ok, thank you again for you in-depth explanations

Answer 20

wlcm