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Please help me solve the following problem. Find a unit vector u that is normal at P(1,-2) to the level curve of f(x,y)=4(x^2)y through P.
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\[f(x,y)=4x ^{2}y\]
FIND THE GRADIENT AND DEVIDE IT BY IT MODULE AT P
ok the gradient is: \[(8xy)i+(4x ^{2})j\]
and divide by the magnitude at the point P?
at P it is (-16,4) so unit vector is: (-16,4)/(sqrt{16^2+4^2))
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you could. But since it is a level function you can get it faster by gradient. Sincé you know that it is always perpendicular to level curves
gradient vector is perpendicular to any level curve !!!
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