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Mathematics 19 Online
OpenStudy (anonymous):

First lesson in radicals (question below)

OpenStudy (anonymous):

\[\sqrt{(a + b)^{2}}\]

OpenStudy (anonymous):

Simplify pls

OpenStudy (mertsj):

This problem is trying to teach you that squaring and taking the square root are inverse operations.

OpenStudy (mertsj):

Addition and subtraction are inverse operations as well.

OpenStudy (mertsj):

Suppose we start with 6 and add 3 and then "undo" that by subtracting 3. What do we end up with?

OpenStudy (anonymous):

We have a term (a+b) that is squared, and then we take the square root. When we square something and then take it's square root, we are left with the absolute value of our original term (it can't be negative since the square root is defined as the positive root) so we would be left with |(a+b)|

OpenStudy (anonymous):

6 right?

OpenStudy (mertsj):

Yes. The very thing that we started with. So look at your problem:

OpenStudy (mertsj):

You take (a+b) and square it.

OpenStudy (mertsj):

Then you do the inverse operation and take the square root. Where does that leave you?

OpenStudy (anonymous):

Oooohhhhhh!! i get it now :) thx so much u two. the answer is a + b

OpenStudy (anonymous):

The answer would be |(a+b)| because you can't end up with a negative after taking a square root.

OpenStudy (mertsj):

Exactly. Good for you. Very important lesson concerning radicals. Similarly:

OpenStudy (mertsj):

\[(\sqrt{3})^2=3\]

OpenStudy (mertsj):

And so on.

OpenStudy (anonymous):

Thx i can now continue my lesson without worrying about understanding the basics :)

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