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Mathematics 20 Online
OpenStudy (anonymous):

10. There are 50 competitors in the men’ s ski jumping. 30 move on to the qualifying round. How many different ways can the qualifying round be selected?

OpenStudy (anonymous):

The choices are: a) 50! b) 30! c) 80 d) 1500 e.) 1.25 * 10^(46)

OpenStudy (anonymous):

I got e), 1.25 * 10^(46) since the answer should be P(50,30). I just need a confirmation. Thanks.

OpenStudy (anonymous):

@Luis_Rivera @Callisto @Hero @TuringTest @mathslover

OpenStudy (anonymous):

By "different ways" I believe what they are suggesting is not that each "different way" needs to give us a different set of qualifiers but instead a different permutation of the set of qualifiers. Also since this is a M/C question, it is clear to see that none of the choices make any sense.

OpenStudy (anonymous):

The only one that makes sense is e), the rest seem to be just "obvious" mistakes someone could make.

OpenStudy (anonymous):

Anyone agrees with my answer???

OpenStudy (anonymous):

@whpalmer4

OpenStudy (anonymous):

@whpalmer4 wherere areee uuuuuuuuuuuuuuuuuuuuuuuuuu

OpenStudy (anonymous):

@whpalmer4 palmy where are u.

OpenStudy (anonymous):

@RadEn You get same answer as me?

OpenStudy (raden):

hmmm... it should 50C30, doesnt it ?

OpenStudy (anonymous):

Ya that's what I got too. I just wanted to confirm whether others get the same answer as me/agree with my answer.

OpenStudy (anonymous):

Wait no, why would it be 50C30

OpenStudy (anonymous):

From the way the question is worded, it wouldn't be "unique group of qualifiers". It would be just the many ORDERS of choosing a qualifying round. That's how I interpreted it. Plus, look at the choices. If this was a combinatorics problem, the choices wouldn't be like that. Also, like I mentioned earlier, another way to confirm that the way I'm interpreting the question is correct and that 50P30 is in fact the right answer is by looking at the first 4 choices. Neither of them make any sense which would make the last choice e) the most appropriate answer. Which is what I got. You know what I'm saying? @RadEn

OpenStudy (raden):

as long as my known, if we want choice r distinct elements from n elements, so just use the combination. note : You use Permutation when order matters. You uce Combination when it doesn't.

OpenStudy (anonymous):

@RadEn I know. Here the question is worded in such a way that suggests that order in fact matters which is why you do 50P30 instead of 50C30. This answer would also make sense because the rest of the choices are absolutely senseless.

OpenStudy (raden):

yeah, i see it... sometimes the option would helps us :)

OpenStudy (raden):

if me, i want choice f) 50C30 hahaha

hero (hero):

I'm sort of an amateur at this, but I'm curious to know why it wouldn't be 30! 50 doesn't matter at all. Only the 30 that moved on to the qualifying round. The remaining 20 didn't make it.

hero (hero):

@RadEn, don't run away, weigh in. I want to get your input on it.

hero (hero):

You too @genius12. Explain your reasoning behind your answer choice.

OpenStudy (raden):

actually, this is a combination problem. that's my transleting problem on this case

hero (hero):

Yes, what is your reasoning that leads you to believe that is the case?

OpenStudy (anonymous):

The reason for why I picked 50P30 is because there is 30 people who are to qualify from 50 correct? So for the first qualifier from the 30, there is 50 choices, for the second there is 49...all the way till the 30th qualifier for whom there is 31 choices. Doing the multiplication we get:\[\bf \prod_{n=31}^{50}x=31 \times 32 \times 33....\times 50=\ _{50}P_{30}=1.25 \times 10^{46}\]This is the value of all the permutations of how the qualifying round can be selected meaning the order in which it could be selected. @Hero

hero (hero):

The 30 have already moved on to the qualifying round. The remaining 20 don't even factor into the equation anymore.

OpenStudy (anonymous):

@Hero Where are you getting that from?

hero (hero):

We'll have to get more people in on this, but I'm confident that I'm correct.

OpenStudy (raden):

but thats not exactly 1.25 x 10^46 50P30 = 1.2501158328406120.... x 10^46

hero (hero):

Maybe you two are right and maybe I'm just mis-interpreting. I think it's kind of dumb question.

OpenStudy (anonymous):

The whole meaning of 50P30 is how many ways can 50 things be arranged in to a group of 30. So if I have numbers set A = {1,2,3..,50}, how many subsets B could I make such that B is a subset of A and has 30 elements and each subset is considering unique if the order of the elements is different.

OpenStudy (anonymous):

@RadEn I think they would run out of space to right that much on the test sheet which is why they took it to 2 decimal places.

OpenStudy (raden):

yeah, maybe

OpenStudy (anonymous):

But using some common sense, do we agree that none of a,b,c,d could be the answers? @RadEn

OpenStudy (raden):

ah i see now.. where there is a competition, must be a winner as rank 1,2,3,4,5,6,...,30. obviously, the order must be concidered. yes it is permutation not combination. i agree with you, @genius12

OpenStudy (anonymous):

:D

hero (hero):

It's still awkwardly worded question. The appropriate way to ask the question is to say: There are 50 competitors in the men’ s ski jumping. 30 will eventually move on to the qualifying round. How many different ways can the qualifying round be selected?

OpenStudy (anonymous):

Now I have a quick question. There is a question I have to draw a tree diagram for. Here is the question: A dice is rolled. A card is drawn from a deck of face cards (i.e. only Jack, Queen, King of each suit). A coin is flipped. a) Draw a tree diagram to define the sample space for this game. Here is the tree diagram I drew, it's attached as a file. Can you guys look at it and tell me what you think of it?

hero (hero):

@genius12, I barely had a chance to get my post responded to.

OpenStudy (anonymous):

@Hero Sorry hero but what was your question?

hero (hero):

It's not that difficult to figure out what my gripe is.

OpenStudy (anonymous):

@Hero Can you say exactly what you're asking instead of using metaphorical speech? I really don't know what your saying when you type "gripe" lol.

hero (hero):

I posted something right before you posted your "Quick Question" post. You didn't see my post because it posted microseconds before yours did.

OpenStudy (anonymous):

Oh are you referring to the post in which you typed up the reworded question? @Hero

hero (hero):

Yes

OpenStudy (anonymous):

what about it

OpenStudy (anonymous):

Like that post isn't interrogative in any way. It simply rewords the question I asked with the addition of the word 'eventually'.

hero (hero):

The eventually is an important word to mention because it alerts to us that we need to consider the 50.

OpenStudy (anonymous):

How? Frankly, the eventually makes no difference.

hero (hero):

Of course it doesn't from your point of view.

hero (hero):

But I think I get it now. The word "selected" is the key word here.

OpenStudy (anonymous):

Ya, and another keyword is "Competitors". It tells us that this in fact is a competition which implies that the qualifiers will be ranked which implies that the order of the qualifiers matters.

hero (hero):

I already knew it was a Permutation. That was never in question from my point of view.

OpenStudy (anonymous):

I see lol. You were questioning about something I didn't get bothered by and I was asking about something you already knew. We have interesting perspectives/point of views.

OpenStudy (anonymous):

But I believe the problem is solved and it's all good. Time to close the question. Any more questions/comments?

hero (hero):

Nope, it is over.

OpenStudy (anonymous):

Nice talking to you. Bye. @Hero @RadEn

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