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Mathematics 20 Online
OpenStudy (explainitlikeimfive):

Determine whether the function is periodic. If it is, find the period.

OpenStudy (explainitlikeimfive):

OpenStudy (explainitlikeimfive):

A. periodic; about 6 B. periodic; about 3 C. periodic; about 12 D. not periodic

OpenStudy (whpalmer4):

Does the function repeat itself exactly? How far is the distance from the dirt time to the second?

OpenStudy (explainitlikeimfive):

I dont know

OpenStudy (whpalmer4):

Well, I suggest you pick a point on the left side of the graph. Scan along the graph the see if that exact value of y appears again on the graph. If not, it is not periodic. If yes, see if the two graphs make identical moves from that point.

OpenStudy (explainitlikeimfive):

I think it is periodic, and it does make identical moves.

OpenStudy (theeric):

It does look like it's repeating itself... So, you agree, @ExplainItLikeImFive , so you can pick out one point, AND then find out where it's repeated in the pattern?

OpenStudy (explainitlikeimfive):

Yes

OpenStudy (theeric):

Okay! So how far away are those points? I mean, the point and where that point is repeated. The distance between them is the "period" and is the answer to your question.

OpenStudy (explainitlikeimfive):

About 6

OpenStudy (theeric):

I agree! \(\huge\color{blue}{\large\ \ o\ o\ \\\smile}\)

OpenStudy (theeric):

Congratulations!

OpenStudy (explainitlikeimfive):

Thanks

OpenStudy (theeric):

Haha, you did the work. And thanks to @whpalmer4 for clearly introducing that great method to see if it was periodic!

OpenStudy (whpalmer4):

The period of this function is probably \(2\pi\approx 6.28\) but of course that isn't an answer choice this time. Expect it to be in the future, however :-)

OpenStudy (theeric):

:)

OpenStudy (whpalmer4):

I didn't give a full description of the method — if the next point at which you have the same y value doesn't behave identically, go to the next point which has a matching y value and try again. Keep trying until you run out of candidates, or find one that works. Probably obvious, but better safe than sorry...

OpenStudy (theeric):

Haha, I like the completion.

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