Question

Can anyone help me with algebraic fractions?

Answer 1

What is the problem?

Answer 2

6/y^2-xy - 6/x^2-xy

Answer 3

what sld i do with 6/y^2-xy - 6/x^2-xy frnd

Answer 4

its supposed to be solved and simplified... but i keep getting it wrong because my answer is 6x^2-6y^2-12xy/xy(-y^2-x^2)

Answer 5

\[6/(y^2-x y)-6/(x^2-x y)\]

Answer 6

\[6(x^2-x y)/(y^2-x y)-6(y^2-x y)/(x^2-x y)\]

Answer 7

\[6(x^2-x y)-(6(y^2-x y))/(y^2-x y)(x^2-x y)\]

Answer 8

\[\frac{ (6x^2-6x y-6y^2+6x y)) }{ (y^2-x y)(x^2-x y) }\]

Answer 9

\[6x^2-6y^2 = 6(x^2-y^2)\]

Answer 10

\[6(x^2-y^2) = 6 (x-y)(x+y)\]

Answer 11

\[\frac{ 6 (x-y)(x+y)}{ y(y-x)x(x-y) }\]

Answer 12

Cancel the (x-y) and Bob's your uncle

Answer 13

thank you so much!!

Answer 14

\[\frac{6}{y^2 - xy} - \frac{6}{x^2 - xy}\]
\[\frac{6}{y(y- x)} - \frac{6}{x( x- y)}\]
\[\frac{6}{y(y- x)} + \frac{6}{x(y-x)}\]
\[\frac{6}{(y- x)}\left(\frac{1}{x} + \frac{1}{y}\right)\]
\[\frac{6}{(y- x)}\left(\frac{y}{xy} + \frac{x}{xy}\right)\]
\[\frac{6}{(y- x)}\left(\frac{y + x}{xy} \right)\]
\[\frac{6(x + y)}{xy(y - x)}\]

Answer 15

No cancelling necessary. Cancelling in this case implies that you computed unnecessary steps.