The graph below shows height as a function of time for a ride on a Ferris wheel. Find a sine equation for the graph.
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OpenStudy (explainitlikeimfive):
OpenStudy (theeric):
Any guesses?
OpenStudy (explainitlikeimfive):
Err, C rather
OpenStudy (anonymous):
check for B
OpenStudy (explainitlikeimfive):
So, Im gonna guesstimate B.
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OpenStudy (theeric):
Why? Haha!
OpenStudy (explainitlikeimfive):
Oh, no particular reason.
OpenStudy (anonymous):
check the amplitude of the graph which is 20 units
OpenStudy (theeric):
Haha, like playing darts with your eyes closed?
OpenStudy (explainitlikeimfive):
Yeah I'm pretty confident with B.
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OpenStudy (anonymous):
the lowest point in the graph is 5 and the highest point is 45 so the mean is at 25 and hence the amplitude is 20
OpenStudy (explainitlikeimfive):
Thanks
OpenStudy (theeric):
Final answer?
OpenStudy (explainitlikeimfive):
Still going with B
OpenStudy (theeric):
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OpenStudy (explainitlikeimfive):
I'm wrong, ar'nt I?
OpenStudy (theeric):
I would agree with your final answer... BUT YOU SHOULD BE CONFIDENT!
OpenStudy (explainitlikeimfive):
*arn't
OpenStudy (explainitlikeimfive):
Success
OpenStudy (theeric):
Haha, I bet the \(\Large\frac{3\pi}{2}\) part threw you off.
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OpenStudy (explainitlikeimfive):
Everything throws me off
OpenStudy (theeric):
Lies...
OpenStudy (theeric):
The thing added to the \(x\), which was \(\Large\frac{3\pi}{2}\) here, is the horizontal shift. Note that sin starts in the middle of its range and then gets bigger. Well, the graph started at \[sin\left(\frac{3\pi}{2}\right)\]when \(x\) was \(0\). I could point out how it works on the unit circle, but I bet that sounds painful.
OpenStudy (explainitlikeimfive):
Yeah, I'm just gonna nod my head in agreement. And we won't take it any further.