Question

123

Answer 1

*maximum height

Answer 2

round to the nearest whole foot

Answer 3

\(V_0=120 \)
\(h_0=2\)
substitute this into: \(h(t)=-16t^2+V_ot+h_o \)
Lter find a vertex of this parábola. This will be your max hight

Answer 4

so -b/2a?

Answer 5

yes

Answer 6

3.75?

Answer 7

and rounding to the neares foot is 4ft?

Answer 8

now put this value instead of t into the equation and find h(t)

Answer 9

227ft why did i need to find that?

Answer 10

because what you found first is t at which ball obtains it's max height, but, ofcourse, it's not the height it self, :)

Answer 11

so my answer is within the range of 3.74-3.76?

Answer 12

your answer = \(-16(3.75)^2+120(3.75)+2\)

Answer 13

so my real answer is 227ft?

Answer 14

yes

Answer 15

yes i got it! thank you!

Answer 16

yw

Answer 17

give the guy a medal. geez.