Question

i dont know how to do this? im posting the problem in the comments its long

Answer 1

\[6\sqrt[4]{4}-7\sqrt[3]{4}+2\sqrt[3]{4}-3\sqrt[4]{4}\]

Answer 2

you have 2 factors, call them u and v

\[6\sqrt[4]{4}-7\sqrt[3]{4}+2\sqrt[3]{4}-3\sqrt[4]{4}\]
\[6u-7v+2u-3v\]
and collect like terms

Answer 3

those radicals are "just a number" and im pretty sure you have no idea what their values are ... so let them be "unknowns" to clean the place up

Answer 4

ok

Answer 5

@Euler271 did you delete your post?

Answer 6

yes. answer was right but the method was pretty bad and lame.

wouldn't really teach anybody lol

Answer 7

@amistre64 can you explain it step by step

Answer 8

i thought i did.

step 1, ignore the messiness

step 2 , add like factors

step 3 , move on to the next problem

Answer 9

we cold make it more complicated if need be .... but that usually not the way they want you to go

Answer 10

@amistre64 i dont remember adding like factors

Answer 11

3x + 5x = ???

Answer 12

3(apples) + 5(apples) = ??(apples)

Answer 13

8x

Answer 14

i dont get it with square roots and cubed roots and all that

Answer 15

thats whats confusing me

Answer 16

the radicals are just "some number".

there are 2 difference radicals, so just clean it up by using 2 different letters

\[6(\sqrt[4]{4})-7(\sqrt[3]{4})+2(\sqrt[3]{4})-3(\sqrt[4]{4})\]
\[6a-7(\sqrt[3]{4})+2(\sqrt[3]{4})-3a\]
\[6a-7r+2r-3a\]
this hasnt changed the nature of the setup, just the way it looks to be able to see it better

Answer 17

add up the like factors
\[6a-7r+2r-3a\]
\[6a-3a-7r+2r\]
\[3a-7r+2r\]
\[3a-5r\]
replace a and r with their respective radicals

Answer 18

ooh ok i get it now thanks

Answer 19

youre welcome