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Mathematics 7 Online
OpenStudy (emilyjones284):

Please help Ill give a medal and a fan (: Ill post the question below.

OpenStudy (emilyjones284):

Solve \[\log x ^{2}+ 1=5\] Round to the nearest tenth if necessary.

OpenStudy (amistre64):

is that log (x^2 + 1) ?

OpenStudy (emilyjones284):

yes

OpenStudy (emilyjones284):

wait so what is the answer?

OpenStudy (amistre64):

log is used in lower maths as a base 10 log; in higher areas, all logs are the natural base e log. do you know the base of the log in this case?

OpenStudy (amistre64):

once you know the base, base both sides to undo the log .. then solve the quadratic

OpenStudy (emilyjones284):

im just checking my answer because im not sure if i did it right

OpenStudy (amistre64):

what was your answer?

OpenStudy (emilyjones284):

10

OpenStudy (amistre64):

log (101) does not equal 5 log (101), if base 10 .. is about 2

OpenStudy (emilyjones284):

oh ok so the answer would be 2?

OpenStudy (amistre64):

no, log(5) does not equal 5

OpenStudy (amistre64):

ill assume the this to be a log base 10 log(x^2+1) = 5 x^2+1 = 10^5 x^2 = 10^5 - 1 x = sqrt{10^5 - 1} or -sqrt{10^5 - 1}

OpenStudy (emilyjones284):

the answer is either 100, 10, 2, or 316.266

OpenStudy (emilyjones284):

so its 316.266 right?

OpenStudy (amistre64):

i beleive so; as long as ive got the setup correctly interpreted :)

OpenStudy (emilyjones284):

Okay thank you (:

OpenStudy (amistre64):

good luck

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