Please help Ill give a medal and a fan (: Ill post the question below.
Solve \[\log x ^{2}+ 1=5\] Round to the nearest tenth if necessary.
is that log (x^2 + 1) ?
yes
wait so what is the answer?
log is used in lower maths as a base 10 log; in higher areas, all logs are the natural base e log. do you know the base of the log in this case?
once you know the base, base both sides to undo the log .. then solve the quadratic
im just checking my answer because im not sure if i did it right
what was your answer?
10
log (101) does not equal 5 log (101), if base 10 .. is about 2
oh ok so the answer would be 2?
no, log(5) does not equal 5
ill assume the this to be a log base 10 log(x^2+1) = 5 x^2+1 = 10^5 x^2 = 10^5 - 1 x = sqrt{10^5 - 1} or -sqrt{10^5 - 1}
the answer is either 100, 10, 2, or 316.266
so its 316.266 right?
i beleive so; as long as ive got the setup correctly interpreted :)
Okay thank you (:
good luck
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