Question

which of these are equivalent to 16^x? select all those that apply.

A. (4*4)^x
B. 4^x*4^x
C. 4^2*4^x
D. 4*4^x
E. 4*4^2x
F. 4^2x

Answer 1

I have A so far

Answer 2

You'll have to use the following facts:
\[16=4\times4\]
\[\large\left(a^b\right)^c=a^{bc}\]

Answer 3

A is right. What else can you get?

Answer 4

well... I was thinking B???

Answer 5

Right! Because \((4^x)\times(4^x)=(4^x)^2=4^{2\times x}=(4^2)^x=16^x.\)

Answer 6

There's at least one more

Answer 7

so... just A & B?

Answer 8

oh

Answer 9

idk

Answer 10

Look at the series of equalities I wrote earlier:\[4^{2\times x}=~?\]

Answer 11

4^2+x

Answer 12

right? ..........

Answer 13

A. \((4*4)^x=16^x\)
B. \(4^x*4^x=4^{2x}\)
C. \(4^2*4^x=4^{2+x}\)
D. \(4*4^x=4^{x+1}\)
E. \(4*4^2x=4^{2x+1}\)
F. \(4^{2x}=4^{2x}\)

Answer 14

so that's the 3rd one?

Answer 15

so it'd be A, b, & f?

Answer 16

no

Answer 17

right? it'd just be A, B, & F