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Mathematics 19 Online
OpenStudy (anonymous):

Choose the system of equations with the graphical solution shown below. (image of a graph with 2 lines intersecting at the point(1,-1)) 5x – y = 6 12x + 6y = 6 5x + y = –6 12x + 6y = 6 5x – y = 6 12x – 6y = 6 5x + y = –6 12x – 6y = –6

OpenStudy (whpalmer4):

Okay, if they intersect at (1,-1) that means x = 1, y = -1 will satisfy all the equations in the system of equations.

OpenStudy (anonymous):

i think its asking what the equations of the two lines would be

OpenStudy (anonymous):

OpenStudy (whpalmer4):

The intersection point will be at (1,-1). There is only one set of equations listed where both equations are true for x = 1, y = -1.

OpenStudy (anonymous):

ohh okay i got it, its A right?

OpenStudy (whpalmer4):

Let's check: 5(1)-(-1) = 6 5+1 = 6 good so far 12x + 6y = 6 12(1) + 6(-1) = 6 12-6=6 looks good!

OpenStudy (whpalmer4):

Now, they could have made this a trickier problem by having a number of different lines that intersected at (1,-1), but didn't match the graph!

OpenStudy (whpalmer4):

There you wouldn't be able to use a shortcut, and would have to puzzle out which equations matched the graph by computing slope, intercepts, etc.

OpenStudy (anonymous):

thank you!

OpenStudy (whpalmer4):

Wouldn't be a bad idea to figure out what those other choices look like, just for practice. The more you do it, the easier it gets.

OpenStudy (whpalmer4):

Here's a tip: you can quickly plot a line by finding the x and y intercepts, marking them, then drawing a line through them. To find the x and y intercepts, just substitute 0 for one variable and solve for the other. For 5x-y = 6, for example, the x intercept (which is where y = 0) is 5x-0 =6, or x = 6/5. You can see if you look at the graph that the line going up to the right crosses the x-axis at x = 6/5. The y intercept (where x=0) is 0-y=6 or y = -6, and sure enough, that line crosses the y-axis at y = -6.

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