Use f(x)=2x-3 and g(x)=1-x^2 to evaluate the following expression

Question

anonymous · Answer

$$(f∘f^{−1})(1)$$

anonymous · Answer

@terenzreignz help? please:)

terenzreignz · Answer

I told you already :P
$$\huge (f\circ f^{-1})(x) = x =(f^{-1}\circ f)(x)$$

anonymous · Answer

im evaluating it... even though im thinking that the answer is just 1

anonymous · Answer

like... im doing whatever we did earlier before you told me that lol

terenzreignz · Answer

And naturally...
$$\huge (f\circ f^{-1})(\color{red}1) = \color{red}1 =(f^{-1}\circ f)(\color{red}1)$$

terenzreignz · Answer

Get it? ^_^

anonymous · Answer

so i don't have to bother with the thing earlier... i think i got the wrong aswer cause i did something weird.. :S

anonymous · Answer

answer*

terenzreignz · Answer

as long as it's $$\huge (f\circ f^{-1})(x) $$
okay?
or $$\huge (g\circ g^{-1})(x) = x)$$
for that matter...
but be careful, if they're not inverses of each other, say...
$$\huge (g\circ f^{-1})(x)$$
Well, in this case, you DO have to work it out... :)

anonymous · Answer

I HOPE I NEVER GET SOMETHING LIKE THE BOTTOM ONE ON MY EXAM !!! D: but okay i get the idea now. gonna make a note on that for my exam thanks !

terenzreignz · Answer

^_^