Represent 375 and 4856 in the Babylonian number system
Now what?
@robtobey
Babylonian number system? -.-
i am have trouble understanding how to put these numbers together using their base 60
Too bad these aren't just numbers from 1 to 59, or this'd be ridiculously trivial :D
Wait, so we have to draw those sticks or whatever?
Unless LaTeX can provide for them :P
ha, yeah.
guess its positional number system with out 0, with 60 digits/symbols
@zonazoo What are you studying by the way?
So mod 60.
need to account for missing 0 also not sure
Okay, so... it seems this is just... place value system with base 60
Let's start with 375.. how many 60's are in 375?
ok, 6
so... unlike our 'normal' system, where we have a place values as ones, tens, hundreds, etc.. They use a sexagesimal system, they have a ones, 60's, 3600's etc....
So, 375 doesn't reach 3600 yet, so we start counting the number of 60's... That's 6. And what remains?
15
@terenzreignz I think the problem is the drawing.
Is it? @zonazoo ?
the difference from 375, or u mean from 3600
@terenzreignz did it correctly.
No, I mean, IS the problem just drawing?
ohh, yes, i dont understand which symbols to use.
@goformit100 I know @terenzreignz is correct. What I'm saying is, once you get above 9, it's hard to represent other digits. Especially in a case of base 60.
So you'll need to use the diagrams explicitly.
ya that is correct.
Here, a place value table... \[\large \left.\begin{matrix}\times & \color{red}{60^2}&\color{red}{60^1}&\color{red}{60^0}\\375 &0&6&15 \\4856 &1 & 20 &56 \end{matrix}\right.\]
there is an example that is given, if you look at the link with the chart above, there is a drawing of 4 symbols... 1, 57, 46, 40... and these when placed next to each other some how mean, 424,000
Yes... it basically means.... \[\Large 1\times 60^3 + 57\times60^2 + 46\times60 + 40\times 60\]
okay, i understand your table.
so your saying for 375, i am going to use the 6th and 15th symbol.
flgbrgerelrjernermernxpodrnxe That's Babylonian for good night fellas.
Whoops, I meant \[\Large \color{red}{1\times 60^3} + \color{green}{57\times60^2} +\color{blue}{ 46\times60^1} + 40\times 60^0\]
And yes, @zonazoo
okay... lets just make up some random number of 53,849.... I would have to figure out how many times 3600 goes into this just to get the first symbol
Yes... Unless somehow, 216000 also goes in...
But it doesn't... So... how many times does 3600 go in?
ummm, looks to be like 13 or 14... maybe 15.... im trying to get this in my head.
14. Don't hurt yourself :D
that seems like what would happen when u deal with large numbers, i couldnt imagine putting this much effort into figuring out how to write a number... so okay 14 x 60^2 + 57 x 60^1 + 29
Yup :) so in babylonian numerals, it'd be 14th symbol, 57th symbol, 29th symbol :D
We actually use the sexagesimal all the time... literally, when telling time :D 60 seconds, 60 minutes... well, that ends there :P
ha. well thanks for all your help.
No problem... :)
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