Question

HELP!














Simplify completely quantity 7 x squared plus 11 x minus 6 all over quantity 7 x squared minus 10 x plus 3

Answer 1

\[\large \cfrac{7x^2+11x-6}{7x^2-10x+3}\] yes?

Answer 2

yes..

Answer 3

quantity 7 x minus 6 over quantity 7 x plus 3
is this correct?

Answer 4

Let me check, :P

Answer 5

okay!

Answer 6

No sorry,that isnt :\

Answer 7

Let's work through it step by step! :D

Answer 8

wait! what about this?
quantity x plus 2 over quantity 7 x plus 3

Answer 9

Starting with the numerator, \(\large 7x^2 +11x -6\), we multiply the leading coefficient wih the constant at the end, \(\large \color{green}7x^2 +11x -\color{green}6\) this helps makeit easier to evaluate our function. We'll have \[\large x^2 +11x -42\]

Answer 10

Nope that isnt an option either :\

Answer 11

Infact, once wwe write this in simplest form, nothing will be reduced! :D

Answer 12

dang -_-

Answer 13

Can you tell me what two numbers multiply to give -42 and add to give +11?

Answer 14

hint: think of your 7's table :P

Answer 15

I get one or negative when when I do 6 and 7 .

Answer 16

well, 7 x ______ = 42?

Answer 17

\[\frac{ 7x ^{2}+11x-6 }{ 7x ^{2}-10x+3 }=\frac{ 7x ^{2}+14x-3x-6 }{ 7x ^{2}-7x-3x+3 }\]
\[=\frac{ 7x \left( x+2 \right)-3\left( x+2 \right) }{ 7x \left( x-1 \right)-3\left( x-1 \right) }\]
\[=\frac{ \left( x+2 \right)\left( 7x-3 \right) }{ \left( x-1 \right)\left( 7x-3 \right) }\]
\[=\frac{ x+2 }{ x-1 }\

Answer 18

we're getting there Surji... haha.

Answer 19

thank you both! ill take it from here and will explain it t myself!

Answer 20

Ok then...

Answer 21

yw

Answer 22

This is my method.
\begin{align}
\large \cfrac{7x^2+11x-6}{7x^2 -10x+3} &= \large \cfrac{x^2 +11x -42}{x^2 -10x +21} \\
&= \large \cfrac{(x-14)(x+3)}{(x-7)(x-3)} \\
&= \large \cfrac{(x-\cfrac{14}{7})(x+\cfrac{3}{7})}{(x-\cfrac{7}{7})(x-\cfrac{3}{7})} \\
&= \large \cfrac{(x-2)(7x+3)}{(x-1)(7x-3)} \\
\end{align}