Question

major help..?

Simplify completely quantity x squared minus 4 x plus 4 over quantity x squared plus 10 x plus 25 times quantity x plus 5 over quantity x squared plus 3 x minus 10

Answer 1

Alright, this one is similar to your previous query.

Answer 2

Lets go over this step by step.

Answer 3

We have
\[{(x ^{2}-4x+4)(x+5)}/({x ^{2}+10x+25)(x ^{2}+3x-10)}\]

Answer 4

hold on a second..i don't think the question you wrote is right..

Answer 5

In the numerator write the first term as \[(x-2)^{2}\]

Answer 6

oh yes its ight I see what you did there okay.

Answer 7

Now in the denominator, write the first term as \[(x+5)^{2}\] and the second term as \[(x+5)(x-2)\]. You can do this using the method I described in your last post (if you remember, otherwise I will be happy to point it out again)

Answer 8

Now you have simplified the entire expression, and all that remains is to simply cancel out the same terms from the numerator and the denominator!

Answer 9

is it okay if you work it all out in one because Its hard for me to do it step by step, I have to see the whole thing. idk if you know what I mean?

Answer 10

i have to explain it to myself i really don't know how to put it in words to tell what i mean haha-_-

Answer 11

Hehe I really don't know what you mean, but do you have a problem understanding a particular step? We can go over it again till you are sure you get it.

Answer 12

can you write how to get the answer all at once? that's what i mean. i understand better if everything is there all at once i tend to explain it to myself better and i get confused if we go one by one.

Answer 13

Hey I can do that, alright, its just that I will have to write all the equations again (and that's not a quick thing to do, lol). But I can explain it in writing, if you are fine with that.

Answer 14

yes thank you.

Answer 15

Start off by writing the question as I wrote it. Then consider one quadratic term at a time. Leave the other term (x+5) as it is. Now write the numerator as \[(x-2)^{2}(x+5)\] Now write the denominator as \[(x+5)^2(x+5)(x-2)\] You get this by using the method I described in your last post. No just cancel the same terms from the numerator and the denominator!

Answer 16

Did you understand it now?