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HELP! Find the exact value of cos(11π/12). Hint: begin by rewriting 11π/12 in terms of familiar angles.
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\[\Huge \cos(\frac{11\pi}{12})=\cos(\pi-\frac{\pi}{12})\]
cos(x+y)= cos x cosy - sin x sin y use this identity
11π/12 = 8π/12 + 3π/12 = 2π/3 + π/4 i would use this
I really don't get how any of that helps me.
\(\bf \huge \frac{11\pi}{12} \implies \frac{8\pi}{12}+\frac{3\pi}{12} \implies \frac{2\pi}{3}+\frac{\pi}{4}\)
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The answer choices are: √6+√2/4 √3+2/4 √3-2?4 -√ 2-√6/4
so, add them then
Use the identity I have posted above. cos(x+y)= cos x cosy - sin x sin y
and your Unit Circle
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Oh man, I got to go thanks for the help, I'll solve it when I get back, I still gave you the medal.
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