Question

HELP! Last algebraic fraction but I can't get solve for x!?

Answer 1

\[\frac{ x+1 }{ 2x+6 }-\frac{ 9 }{ x ^{2}-9}=\frac{ x-2 }{ 2x-6 }\]

Answer 2

\[\frac{ x+1 }{ 2(x+3) }-\frac{ 9 }{ (x+3)(x-3)}=\frac{ x-2 }{ 2(x-3) }\]
\[\frac{1}{x+3}(\frac{ x+1 }{ 2 }-\frac{ 9 }{(x-3)})=\frac{ x-2 }{ 2(x-3) }\]
\[2(x-3)(\frac{ x+1 }{ 2 }-\frac{ 9 }{(x-3)})=(x-2)(x+3)\]

Answer 3

\[(x-3)(x+1)-18=(x^{2}+x-6)\]
\[x^{2}-2x-3=x^{2}+x-6\]

Answer 4

Sorry, that should have been \[x^{2}-2x-21=x^{2}+x-6\]

Answer 5

-15-3x=0, -3x = 15, x = -5

Answer 6

:)

Answer 7

woah that helped a lot thanks!

Answer 8

Check my math, and you're welcome. :)

Answer 9

x = -5 is correct.